Abstract: Let W be a twisted I-bundle over a Klein bottle fibered trivially whose base space is a Mobius band and V be a (p,q)-fibered solid torus. Since the boundaries of V and W are tori, we may form a quotient space N by identifying the boundary tori. Let f : bd(V ) -> bd(W) denote the glueing map. One can choose f to be a fiber preserving map. Next, we let N = V \cup_{f} W be such the quotient space. As the attaching preserves the fiber, N is also a (p,q)-fibered Seifert fibered space, which is known as a prism manifold. We can observe that the base space of N is topologically a real projective plane that contains at most one cone point of order p.In the talk, we will carefully observe that N is double covered by a symmetric lens space L, which gives us a geometric structure on N. It turns out that L and Isom(N) are completely determined by the initial assignment of a fibration type on V. We will observe how a fibration type affects topological structures on N and L as well as Isom(N). Moreover, this allows us to compute the isometry group of N denoted by Isom(N).The technique to compute Isom(N) depends on the liftability criteria, that is, if h : L -> N is a covering map and if g \in Homeo(N), then there is \bar{g}: L \rightarrow L such that h \circ \bar{g} = g \circ h if and only if g_* \circ h_* (\pi_1(L)) is a subgroup of h_*(\pi_1(L)).Unfortunately, the liftability does not work in certain cases. Thus, Isom(N) was not able to classify completely in my last talk. In these cases, a "pullback" method will be used. In other words, we will use the fact that there is a subgroup in S^3 \oplus S^3 and an epimorphism \hat{\rho} such that image of the subgroup under \hat{\rho} is Isom(N). Further, the key ingredient to determine Isom(N) is as follows: If G_1 and G_2 are any finite non-cyclic subgroups of Isom_+(S^3) = SO(3) such that G_1 \cong G_2 and acting on S^3 freely, then the two groups are a difference of some conjugate. This will give us the complete classification of Isom(N).