Difference between revisions of "Egyptian Geometry Exploration"
Revision as of 09:27, 24 January 2009
1. In problem 6 of the Moscow Papyrus the sides of a rectangular region are computed, given the area.
a. What would the Egyptian solution be if the area enclosed 15 units? Write out the solution as they would have.
b. Using these two examples (i.e the one from ancient Egypt and the example you just did) explain how the lengths of the sides are computed.
c. Write out a modern American solution of the problem using the variables x and y for the lengths of the sides. Write out a detailed solution showing all your work.
d. Are the solutions basically the same? Different?
e. Which explanation do you find easier to follow? The Egyptian version or the American version?
2. In problem 14 of the Moscow papyrus the volume of a frustrum (truncated pyramid) is computed.
a. Using the Egyptian method find the volume if the base is a square of side 2 cubits, the top is a square of side 3 cubits and the height of the truncated pyramid is 5 cubits.
b. Using the Egyptian method find the volume if the base is a square of side x cubits, the top is a square of side y cubits and the height of the truncated pyramid is z cubits.